A 12.45g aluminum metal strip is placed into an 2.3 x 10-1 mol/L solution of tin (II) bromide. If all the aluminum and tin (II) bromide react, what was the volume of the tin (II) bromide solution.
Balanced equation is this right?
Al2+ 2Sn2Br2 --> 2AlBr2+2Sn2
If not help?
2007-04-30 10:35:32 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
The equation given is not correct.
2 Al + 3 Sn2+ ---> 2 Al3+ + 3 Sn
The equation in net ionic form is sufficient to answer this question.
1) calculate moles of Al
12.45 g divided by 26.98 g/mol equals 0.46145 mol
2) Use the following ratio & proportion to solve for moles of Sn2+
0.46145 mol over 2 equals x over 3
x = 0.692 mol of Sn2+
3) Using molarity = moles divided by volume, we solve for the volume
volume = 0.692 mol divided by 0.23 mol / L = 3.0 L
Note that the answer is given to two significant figures, this being dictated by the 0.23 value for the molarity.
2007-04-30 11:11:44 · answer #1 · answered by ChemTeam 7 · 0⤊ 0⤋
A redox reaction is created from 2 a million/2 reactions: a million) alleviation a million/2 reaction 2) Oxidation a million/2 reaction one way i like to bear in mind the version between the two is "LEO the lion does GER" "LEO" stands for "lose electron oxidation" "GER" stands for "benefit electron alleviation" So in a nutshell, what loses electrons is getting oxidized, so that's the reducing agent and what constructive aspects electrons is decreased, so that's the oxidizing agent. I dont somewhat know ways lots explaining your inquiring for, yet i wish this enables good success on your examination :)
2016-12-28 05:28:25 · answer #2 · answered by westbrook 3 · 0⤊ 0⤋
Al2, Sn2Br2, AlBr2, and Sn2 are incomprehensible.
2Al + 3SnBr2 ===> 2AlBr3 +3Sn
Begin with 12.45gAl. I think you can work it out from there.
2007-04-30 10:52:04 · answer #3 · answered by steve_geo1 7 · 0⤊ 0⤋
2Al + 3SnBr2 -----> 2AlBr3 + 3Sn is your equation.
2007-04-30 10:43:14 · answer #4 · answered by Gervald F 7 · 0⤊ 0⤋