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3 answers

The constants are relatively prime, and the first term has no "b", so the answer is the smallest exponent of "a" in any of the terms, which would be a^3.

2007-04-30 10:33:28 · answer #1 · answered by McFate 7 · 0 0

7a^5 + 2a^3 b^2 - 3a^5 b^2 + 4a^4 b^3
The first term only has 7 and a^5. 7 is prime, and none of the other constants are multiples of 7, so, that will leave us with some multiple of a. The smallest a is a^3. So factor that out and get:
a^3(7a^2+2b^2-3a^2b^2+4ab^3)

2007-04-30 10:49:17 · answer #2 · answered by Anonymous · 0 0

7a^5+2a^3b^2-3a^5b^2+4a^4b^3

GCF is a^3
a^3(7a^2+2b^2-3a^2b^2+4ab^3)

2007-04-30 10:32:34 · answer #3 · answered by yupchagee 7 · 0 0

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