2007-04-30 10:24:47 · 8 answers · asked by lindasalicea 1 in Science & Mathematics ➔ Mathematics
5x + 8 = 43
2x + 1 = 15
2007-04-30 10:30:04 · answer #1 · answered by McFate 7 · 0⤊ 0⤋
1(7) +3 = 10
2007-04-30 10:32:51 · answer #2 · answered by p v 4 · 0⤊ 0⤋
Ok, so we have to find something that has 7 as a solution. Ok, let's start with plugging in 7 for a solution of x:
a(7) + b = c
Now we must plug in values for a and b and solve for c so we know that 7 will be a solution:
Let's say that:
a = 2
b = -14
Now we plug in and solve:
2(7) - 14 = c
0 = c
So your equation is:
2x - 14 = 0
And there you go.
2007-04-30 10:31:24 · answer #3 · answered by Eolian 4 · 0⤊ 0⤋
As x=7 give random values to a and b and calculate c
Let a=3 and b=5
a*x+b = c
3*7+5 = c
21+5 = c
c = 26
So 3x+5 = 26 returns x=7
2007-04-30 10:30:31 · answer #4 · answered by Anonymous · 0⤊ 0⤋
ax+b=c
ax=c-b
x=7=(c-b)/a
possibilities include
a=1, b=0, c=7
a=1, b=1, c=8
a=1, b=2, c=7 etc
a=2, b=0, c=14
a=2, b=1, c=15 etc
a=2, b=-7, c=7
& an infinite number of others.
2007-04-30 10:30:48 · answer #5 · answered by yupchagee 7 · 0⤊ 0⤋
5x + 2 = 37
2007-04-30 10:29:45 · answer #6 · answered by Anonymous · 0⤊ 0⤋
There are infinite answers to these. Like:
x+2 = 9
or x + 1 = 8
or 2x + 1 = 15 ..... and so on and on...
2007-04-30 10:29:40 · answer #7 · answered by B 2 · 0⤊ 0⤋
7x - 49 = 0
6x - 42 = 0
etc.
2007-04-30 10:36:29 · answer #8 · answered by edward_otto@sbcglobal.net 5 · 0⤊ 0⤋