find the equation of the axis of symmetry, and find the coordinates of the vertex.
f(x) = x² - 4x
2007-04-30 10:05:12 · 3 answers · asked by soccerstar11 3 in Science & Mathematics ➔ Mathematics
x=2
vertex at (2, -4)
2007-04-30 10:09:28 · answer #1 · answered by RandomNormality 3 · 0⤊ 0⤋
This equation can be written as f(x) = ( x -2)^2 -4. We readily see this function, a parabola, is symmetric about the vertical axis x =2.
The vertex, therefore, has coordinates (2, -4)
2007-04-30 17:13:45 · answer #2 · answered by Steiner 7 · 0⤊ 0⤋
y = ax^2 + bx + c
where here a= 1 and b = -4
the x coordinate of the vertex is found in using the following equation
x = -b/2a
x = -(-4)/2 = 2
plug this into the equation to get the value of y
y = -4
(2,-4)
2007-04-30 17:13:01 · answer #3 · answered by Sergio 2 · 0⤊ 0⤋