L1 through (–4, –7) and (1, 3)
L2 through (2, 6) and (4, 10)
2007-04-30 09:34:14 · 6 answers · asked by QM 1 in Science & Mathematics ➔ Mathematics
m1 = (3+7)/(1+4)=10/5=2
m2=(10-6)/(4-2)=4/2=2
They are parallel.
2007-04-30 09:38:04 · answer #1 · answered by ClevelandRocker 3 · 1⤊ 0⤋
parallell.
The slopes of L1 and L2 can be calculated.
s1 = (3-(-7))/(1-(-4))=10/5=2
s2=(10-6)/(4-2)=4/2=2
The slopes of L1 and L2 are equal. Hence, they are parallel.
Actually, equations of L1 and L2 are:
L1: y = 2*x+1,
L2: y = 2*x+2.
2007-04-30 16:43:27 · answer #2 · answered by YC 1 · 0⤊ 0⤋
calculate the slopes:
m1 = 3-(-7)/(1-(-4)) = (3+7)/(1+4) = 10/5 = 2
m2 = (10-6)/(4-2) = 4/2 =2
If the lines were parallel, then m1 = m2
If the lines were perpendicular then m1 = 1/m2
Parallel
2007-04-30 16:41:12 · answer #3 · answered by T 5 · 0⤊ 1⤋
The first has slope 2 and the second has slope 2, so they are parallel.
2007-04-30 16:38:26 · answer #4 · answered by bruinfan 7 · 0⤊ 0⤋
parallel
2007-04-30 16:37:47 · answer #5 · answered by Anonymous · 1⤊ 0⤋
neither.
2007-04-30 16:45:30 · answer #6 · answered by rosecolured 4 · 0⤊ 0⤋