Reaction: 2HCI + Ca(OH)2-----> 2H2O + CaCl2
2007-04-30 06:18:31 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
HCl is a strong acid that will donate 2.6 moles of free hydrogen to solution; Calcium Hydroxide is a strong base that will donate 2 equivalents of the hydroxide ion to solution. The two will neutralize to form water. The 2 equivalents of hydroxide from the calcium hydroxide is like adding 2.8 (2 times 1.4) moles of NaOH to solution. The neutralization will occur with 2.6 moles of water being formed, 2.6 moles of hydrogen reacting with 2.6 moles of hydroxide. .2 moles of hydroxide will remain in excess or .1 MOLES of Ca(OH)2 is in EXCESS.
2007-04-30 06:37:39 · answer #1 · answered by merz_drm 2 · 0⤊ 0⤋
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2016-05-17 07:46:38 · answer #2 · answered by Anonymous · 0⤊ 0⤋
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2016-12-05 02:56:40 · answer #3 · answered by ? 3 · 0⤊ 0⤋
1.4 x 2 = 2.8, so you haven't got quite enough HCl.
2007-04-30 06:25:30 · answer #4 · answered by Gervald F 7 · 0⤊ 0⤋