what is max depth the submarine can go w/o damage to porthole?
2007-04-30 06:16:17 · 5 answers · asked by Jon S 1 in Science & Mathematics ➔ Physics
I assume that pressure you are referring is in Pascals or Newton/meter (1 atm = 101 325 Pa)
and if 10 m below water surface is 1 atm
#Atm=1.88 E+6 /101 325 =18.6
or 186 meters (you better beef up that porthole ;-) )
P=F/A
F=P A
F= P piR^2=
F=1.88 E+6 x 3.14159.. (.3)^2
F=531600 N
2007-04-30 06:30:03 · answer #1 · answered by Edward 7 · 0⤊ 0⤋
I guess you mean force, not pressure when you say 1.88x10 to sixth N.
1. Find area of the glass.
2. work out pressure which will give you the force 1.88x10^6N
p= F/A (A from step1).
3. p = dgh
where p is the pressure
d is the density of the liquid
g is the local value of gravitational acceleration
h is the height of the liquid surface above the glass
and so by rearranging the equation the distance below the surface of a liquid is given by:
h = p/dg
The density of sea-water is about 1027 kg/m3.
best not to have a porthole then
2007-04-30 08:47:18 · answer #2 · answered by ffordcash 5 · 0⤊ 0⤋
Max. depth?? ...depends on the thickness of the glass, quality of the glass and ratio of thickness to width of porthole (bigger the better). Also on wether the glass is convex (bulges outwards like the surface of a bubble)
I'm sure there are tables online which show the failiure depth and pressure
2007-05-03 08:49:10 · answer #3 · answered by Anonymous · 0⤊ 0⤋
You need to give pressure units i.e. kg/cm², kPa, Bar etc.. or the total force acting on the on the area of the porthole.
2007-04-30 06:34:28 · answer #4 · answered by Norrie 7 · 0⤊ 0⤋
what units of pressure are you using?
every 10 meters of pressure = 1 atmosphere
so if you are at 30 meters the absolute pressure= 4 atmospheres.
40m= 5 atmospheres etc
2007-04-30 06:26:15 · answer #5 · answered by Icarus 6 · 0⤊ 0⤋