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A window has the shape of a semi-circle placed on top of a rectangle.

Express the area A of the window in terms of the width w and height h of the rectangle

2007-04-30 05:10:38 · 6 answers · asked by sdfsdf g 1 in Science & Mathematics Mathematics

6 answers

let r = radius of the semicircle.

Then r = w/2.

A = (area of semicircle) + (area of rectangle)
A = (1/2)pi*(w/2)^2 + wh
A = (pi/8)*w^2 + wh

2007-04-30 05:15:50 · answer #1 · answered by wala_lang 2 · 0 0

One side of the rectangle will equal the diameter of the semi circle. The area of the window, to include the rectangle and the semi circle will be equal to the area of the rectangle (L x W) plus the area of the semicircle, which will be equal to half the side of the rectangle that matches the circle (this will be the radius) squared then times pi, then divided by 2.

2007-04-30 12:22:26 · answer #2 · answered by Anonymous · 0 0

This question is not completely clear, as it doesn't say if the semicircle is on the length or the width of the rectangle. You could say it must be along the width, since it says it "on top", but it should be much clearer.

Anyway, if it is along the width, than the diameter of the circle is equal to the width, so the area is (pi(w/2)/2)+(w*L)

2007-04-30 12:45:37 · answer #3 · answered by soelo 5 · 0 0

You want entire area of the rectangle and a half-circle (ie, semi-circle) area.

For rectangle: A = bh
For full circle: A = pi*r^2, so for half-circle divide by 2.

Sum together for total area.

2007-04-30 12:18:54 · answer #4 · answered by dwalon2 4 · 0 0

A=wh+(pi/2(w/2)^2

=wh+pi/8 w^2

2007-04-30 12:15:34 · answer #5 · answered by iyiogrenci 6 · 0 0

wh + (22/7)x(w/2)2

last 2 is square.

1st bracket is value of pie

2007-04-30 12:22:29 · answer #6 · answered by ravi 1 · 0 0

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