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Two loudspeakers are placed at either end of a gymnasium, both pointing toward the center of the gym and equidistant from it. The speakers emit sound that is in phase. An observer at the center of the gym experiences constructive interference. After walking 0.29 m toward one of the speakers, the observer first experiences destructive interference
(a) Does the required distance x (to move from the constructive interference to the destructive interference) increase, decrease, or stay the same if the frequency of the speakers is lowered?


(b) Calculate x if the frequency emitted by the speakers is lowered by 4% (answer in meters)?

2007-04-30 04:48:33 · 1 answers · asked by blazedup145 1 in Science & Mathematics Physics

1 answers

0.29 = λ/2
(a) As the frequency is lowered, the distance from constructive to destructive interference increases.
(b) d/0.29 = 1/0.96
d = 0.302 m

2007-04-30 18:57:14 · answer #1 · answered by Helmut 7 · 0 0

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