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Which system of inequalities would have all of quadrant III as its solution set?
y > 0 and x > 0
y < 0 and x < 0
y > 0 or x < 0
x = y

2007-04-30 04:45:15 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

quadrant I is when x>0 and y>0
quadrant II is when x<0 and y>0
quadrant III is when x<0 and y<0
quadrant IV is when x>0 and y<0

1.y>0 and x>0
will be in the first quadrant

2. y<0 and x<0
will be in the third quadrant

3. y>0 or x<0
will be in the first and second quadrant OR in the second and third quadrant

4. x = y
will be in the first and third quadrant (look for quadrant where x and y will have the same positive or negative sign)

This leave you only with 2.

2007-04-30 04:59:28 · answer #1 · answered by MadamX 2 · 0 0

y < 0 and x < 0

2007-04-30 04:50:31 · answer #2 · answered by iyiogrenci 6 · 0 0

As you must know: In the first quadrant is x>0 and y>0.
In the second quadrant: x<0 and y>0.
In the third: x<0 and y<0, in the fourth: x>0 and y<0.
You can read the right answer from this.

2007-04-30 05:03:49 · answer #3 · answered by Anonymous · 0 0

y<0 and x<0. That's what the third quadrant is: the lower left quarter of the Cartesian plane. You call the top right quarter "#1" and number the rest going counter-clockwise.

2007-04-30 04:50:11 · answer #4 · answered by Anonymous · 1 0

9.seventy 5 mph rationalization: this may well be a confusing question considering which you at the instant are not given the present, which of course slows the boat on the 1st leg and speeds it up on the 2nd. the substantial right it fairly is that the present is a relentless (if it weren't, we could no longer sparkling up the issue). this is measured in miles per hour and on the upstream holiday it impacts the boat for 4 hours, yet on the downstream holiday, basically for 2.5 hours. So the present fairly has extra effect on the 1st area of the holiday than the 2nd. this is why you may not basically average the holiday (the boat lined 60 miles - 30 plus 30 - in 6.5 hours - 4 plus 2.5) right here is how I solved it: permit x = the cost of the boat in nonetheless water permit y = the cost of the present 4(x-y)=30 4 hours of boat velocity minus modern-day is 30 miles 2.5(x+y)=30 2.5 hours boat velocity plus modern-day is 30 miles using the 1st equation, sparkling up for y in terms of x. 4(x-y)=30 4x-4y=30 -4y=30-4x y=x-7.5 now insert the hot description of y into the 2nd equation 2.5(x+y)=30 turns into 2.5(x+x-7.5)=30 now sparkling up for x 2.5(x+x-7.5)=30 2.5(2x-7.5)=30 5x-18.seventy 5=30 5x=40 8.seventy 5 x=9.seventy 5 the cost of the boat in nonetheless water is 9.seventy 5 mph

2016-12-10 15:24:33 · answer #5 · answered by bickley 4 · 0 0

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