hi i would like to find out how to solve this question.
i would like to find dy/dx given y = e^-5 x ln(4 x).
thanks for any help. it is very much appreciated
2007-04-30 04:25:38 · 4 answers · asked by zz06 3 in Science & Mathematics ➔ Mathematics
I'm going to assume y = (e^-5x)*ln(4x) = f(x)*g(x)
dy/dx = f'(x)*g(x) + f(x)*g'(x)
= -5*(e^-5x)*ln(4x) + (e^-5x)*(1/4x)*4
= (e^-5x)*(-5ln(4x) + 1/x)
2007-04-30 04:34:06 · answer #1 · answered by dudara 4 · 0⤊ 0⤋
I can't figure out if everything after the carat is in the exponent or that the expression is something else. Can you clarify?
2007-04-30 11:29:13 · answer #2 · answered by cattbarf 7 · 0⤊ 0⤋
y = e^(-5x).ln(4x)
dy/dx = - 5.e^(-5x).ln(4x) + (1/x).e^(-5x)
dy/dx = - e^(-5x) [ 5 ln(4x) - 1 / x ]
2007-04-30 11:42:18 · answer #3 · answered by Como 7 · 0⤊ 0⤋
Can you disambiguate it? I'm not sure if you mean
y = e^[-5x ln(4x)]
-OR-
y = e^(-5x) ln(4x)
2007-04-30 11:28:34 · answer #4 · answered by Puggy 7 · 0⤊ 0⤋