A building was supposed to be 30 3/4 x 60 3/8 . How do I find the area?
2007-04-30 02:10:13 · 6 answers · asked by Harley 1 in Science & Mathematics ➔ Mathematics
30 3/4 = 123 / 4
60 3/8 = 483 / 8
(123/4) x (483/8) = 59409 / 32 = 1856 17/32
2007-04-30 02:18:09 · answer #1 · answered by Mathematica 7 · 0⤊ 1⤋
The "x" means multiply so just multiply the 30 3/4 to 60 3/8 to find the area. Good Luck.
2007-04-30 09:19:58 · answer #2 · answered by Olive 1 · 0⤊ 0⤋
Convert both mixed numbers to improper fractions
30 3/4 x 60 3/8 =
123 / 4 x 483 / 8 =
59409 / 32 =
1856 17/32
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2007-04-30 09:49:35 · answer #3 · answered by SAMUEL D 7 · 0⤊ 0⤋
30 3/4 = (4*30+3)/4 = 123/4
60 3/8 =483 /8
now multiply and find the area
P.S.(though a buillding is 3 dimensional figure , how will you find it using only 2 dimensions only???)
2007-04-30 09:20:02 · answer #4 · answered by mR.qUESTiON?? 2 · 0⤊ 0⤋
There is a lack of information here.
First, do the measurement given pertains to the base of the building or it is the height and width of the building?
How many faces is the building?
If it is the height and weight of the building, the area of ONE face of the building is
Area = 30 3/4 x 60 3/8
Area = 30.75 x 60.375
Area = 1,856.53 unit squared ===> this area is only for One face of the building
2007-04-30 09:21:52 · answer #5 · answered by detektibgapo 5 · 0⤊ 0⤋
see that x between those numbers?
to find the area, take that x to mean you multiply the 2 numbers, that will be your area.
2007-04-30 09:14:30 · answer #6 · answered by PoseidenNeptuneReturns 4 · 0⤊ 0⤋