What is the percent yield of CuS for the following reaction given that you start with 15.5 grams of Na2S?

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What is the percent yield of CuS for the following reaction given that you start with 15.5 grams of Na2S?

and 12.1 grams CuSO4? the actually amount if CuS produced was 3.05 grams REACTION: Na2S + CuSO4 > Na2SO4 + CuS

2007-04-29 20:08:38 · 1 answers · asked by alicia r 1 in Science & Mathematics ➔ Chemistry

1 answers

Molar mass of Na2S = 78 g
Molar mass of CuSO4 = 159.5 g

Moles of Na2S = 0.1987

Moles of CuSO4 = 0.0759

Thus 0.0759 of CuS will be formed = 0.0759*95.5 g
= 7.248 g

%age yield = 42.08%

2007-04-29 22:05:21 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋