under certain conditions the reaction will proceed at 29.8% yield of NO How many grams of NH3 must be made to react with excess oxygen to yield 70.5 grams NO???
under certain conditions the reaction will proceed at 29.8% yield of NO. How many grams of NH3 must be made to react with excess oxygen to yield 70.5 grams of NO.
2007-04-29 19:57:01 · 2 answers · asked by alicia r 1 in Science & Mathematics ➔ Chemistry
Molar mass of NH3 = 17
Molar mass of NO = 30
Thus 30 g now actually come from = 17/0.298
Thus, 70.5 g will come from = 17*70.5/(0.298*30)
= 134.06 g
2007-04-29 22:05:23 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Molar mess of NO 30
NH3 is 17
4NH3+5O2----4NO+6H2O
68 120
x 70.5
x=68*70.5/120=39.95
and the will proceed at 29.8% yield of NO
so we need NH3 `S mass is 39.95/29.8%=134.06
2007-04-30 01:48:39 · answer #2 · answered by Xu D 2 · 0⤊ 0⤋