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6 answers

Equation of a circle is (x - h)^2 + (y - k)^2 = r^2

Where (h,k) is the center and r is the radius.

In this case, (h,k) is (6,0) and r = 7.

2007-04-29 19:03:58 · answer #1 · answered by Anonymous · 0 0

you're able to have revealed the equation as below. (x + 5)^2 + (y + 3)^2 = 40 9 ^2 ability squarred. The equation of a circle with centre (h, ok) and radius r is given by (x - h)^2 + (y - ok)^2 = r^2 comparing, centre is (-5, -3) and radius is 7.

2016-12-10 15:10:51 · answer #2 · answered by ? 4 · 0 0

quadriatic equation of a circle

(x - p)^2 + (y - q)^2 = r^2
where
p = x coordinate of the center
q = y coordinate of the center
r = radius

so, the center is at (6, 0) radius = 7

2007-04-29 19:18:53 · answer #3 · answered by calpal2001 4 · 0 0

These people doing the problem for you should be ashamed. You really should do your OWN homework.

A good place to start for help is asking your teacher to help you afterschool in timely manner and not asking a computer at 2 pm at night (eastern time).

If you are waiting until the last minute to do hw, there are a TON of places to look up the equation for a circle. The first person who posted gave you the formula, but that's not enough. You should also figure out WHY that is the equation, etc. Talk to your teacher, please.

I don't mean this to be rude, but I'm really saddened by the lack of effort among people to actually do their own middle school/high school homework.

2007-04-29 19:13:19 · answer #4 · answered by existenz48162 3 · 0 1

(x - 6)² + (y - 0)² = 7²
Centre (6,0)
Radius 7

2007-04-29 19:32:07 · answer #5 · answered by Como 7 · 0 0

center (6,0)
radius = 7

2007-04-29 19:04:10 · answer #6 · answered by Yssa A 3 · 0 0

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