f(x) = 3x - 1 and g(x) = x^2 + 2x - 4, find f(g(x) )
2007-04-29 16:44:12 · 6 answers · asked by awwily 1 in Science & Mathematics ➔ Mathematics
f(g(x) )=( 3 (x^2+2x-4) -1
= (3x^2+6x-12)-1
= 3x^2+6x-13
2007-04-29 16:49:03 · answer #1 · answered by apple 3 · 0⤊ 1⤋
That is simple enough:
Let big X, i.e. X = g(x) = x^2+2x-4.
f(x) = 3x-1, so, f(X) = 3(X)-1 = 3(x^2+2x-4)-1.
Just multiply by 3 from there and subtract 1.
2007-04-29 23:51:44 · answer #2 · answered by jl2000 2 · 0⤊ 0⤋
f(x) = 3x - 1 and g(x) = x^2 + 2x - 4, find f(g(x) )
Put g(x) into f(x)
then
f(g(x) )= 3( x^2 + 2x - 4 ) -1
= 3x^2 + 6x -13
2007-04-29 23:49:52 · answer #3 · answered by looikk 4 · 0⤊ 0⤋
f(x) = 3x - 1 and g(x) = x^2 + 2x - 4, find f(g(x) )
f(g(x)) = f(x^2 + 24 - 4)
= 3(x^2 + 24 - 4) - 1
= 3x^2 + 72 - 12 -1
= 3x^2 + 72 -13
2007-04-29 23:49:09 · answer #4 · answered by aquarian8502 2 · 0⤊ 0⤋
f(g(x))= f( (x^2 +2x-4)= 3(x^2 +2x -4) = 3x^2 +6x -12-1
way too many shift keys on this, yuk
2007-04-29 23:50:13 · answer #5 · answered by Mary E 3 · 0⤊ 0⤋
f(g(x)) = 3(x^2 + 2x - 4) - 1
3x^2 + 6x - 12 - 1
3x^2 + 6x - 13
2007-04-29 23:50:55 · answer #6 · answered by TychaBrahe 7 · 0⤊ 0⤋