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4 answers

g(3) - g(2).

This is the Fundamental Theorem of Calculus.

2007-04-29 16:13:17 · answer #1 · answered by Scarlet Manuka 7 · 0 0

-you'd have to set up an integral with upper bound 3 and lower bound 2.
-and you know that if g'(x)=f(x), then g(x)= integral of f(x)
-then using the Fundamental Theorem of Calculus, you'd first have to plug in 3 into the integral of the f(x) equation (aka g(3)) and subtract from that the same equation except with 2 plugged in. it would look like this:
1) set the equation:
3
∫ f(x) dx
2
2) [g(x)] upper:3, lower: 2
3) g(3)-g(2)

hope this helps
I'm in calculus too :)

2007-04-29 23:41:42 · answer #2 · answered by Ms. Elisa 3 · 0 0

g(3) - g(2)

2007-04-29 23:13:30 · answer #3 · answered by Anonymous · 0 0

g(3) - g(2). sice f is the derivative of g, g is the integral of f.

2007-04-29 23:13:16 · answer #4 · answered by holdm 7 · 0 0

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