2007-04-29 16:05:36 · 4 answers · asked by fireboy5516 1 in Science & Mathematics ➔ Mathematics
You take 1/2 of the coefficient of the x term, 16, and square it.
This will be: 1/2 of 16 = 8 and 8^2 = 64. Add this number.
So you will have x^2 + 16x + 64 which will factor as (x + 8)^2.
Do the same for the other problem. Take 1/2 of the coefficient of the x term, -6, and square it.
This will be: 1/2 of -6 = -3 and (-3)^2 = 9. Add this number.
So you will have x^2 - 6x + 9 which will factor as (x - 3)^2.
good luck!
2007-04-29 16:09:42 · answer #1 · answered by birdwoman1 4 · 0⤊ 0⤋
You complete the square by taking the x coefficient, dividing it in half, and squaring it.
x^2 + 16x
16/2 = 8
8^2 = 64
x^2 + 16x + 64
x^2 - 6x
-6/2 = -3
-3^2 = 9
x^2 - 6x + 9
2007-04-29 16:11:11 · answer #2 · answered by TychaBrahe 7 · 0⤊ 0⤋
64:
x^2 + 16x + 64 = (x + 8)^2
9:
x^2 - 6x + 9 = (x - 3)^2
2007-04-29 16:11:16 · answer #3 · answered by rooster1981 4 · 0⤊ 0⤋
x²+16x + 8² as well as x²-6x + 3²
or
x² + 16x + 64 and x² - 6x + 9
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2007-04-29 16:25:53 · answer #4 · answered by aeiou 7 · 0⤊ 0⤋