Calorimetery?

Question

When 112 g of water at a temperature of 22.5°C is mixed with 65.1 g of water at an unknown temperature, the final temperature of the resulting mixture is 48.0°C. What was the initial temperature of the second sample of water?

Answer 1

112(48-22.5) = 65.1(T-48)

so, T = 91.87 deg C