Chemistry help please?

A 237 g piece of molybdenum, initially at 100.0°C, is dropped into 244 g of water at 10.0°C. When the system comes to thermal equilibrium, the temperature is 15.3°C. What is the specific heat capacity of molybdenum?

2007-04-29 15:20:14 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry

1 answers

s = 244(15.3-10)/{237*(100-15.3) = 0.064 cal/g/deg C

2007-04-29 22:57:14 · answer #1 · answered by ag_iitkgp 7 · 0⤊ 0⤋

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