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2 answers

Solubility = 9.24x10^-4 g/l

Molar mass of Mg(OH)2 = 58

Molarity = 1.59x10^-5 M

of OH- = 3.18 x 10^-5 M

So, pOH = -log(3.18x10^-5) = 4.5

So, pH = 14 - 4.5 = 9.5

2007-04-29 22:57:19 · answer #1 · answered by ag_iitkgp 7 · 0 0

how did you get 3.18*10^-5

2014-10-21 20:57:08 · answer #2 · answered by sonia 1 · 0 0

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