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polynomial having zeros - 8, - 2, 3 and 8 and the coefficient of x^4 equal 1

The polynomial is =

2007-04-29 14:57:43 · 3 answers · asked by bmorekid05 1 in Science & Mathematics Mathematics

3 answers

(x+8)(x+2)(x-3)(x-8)
is a "polynomial having zeros - 8, - 2, 3 and 8 and the coefficient of x^4 equal 1"

If x = -8, then the first factor is zero
If x = -2, then the second factor is zero
etc.

x^4 - x^3 - 70x^2 + 64x + 384

2007-04-29 15:02:37 · answer #1 · answered by Raymond 7 · 0 0

If r is a zero of a polynomial, then x-r is a factor.
So your polynomial is
(x+8)(x+2)(x-3)(x-8) = x^4 -x³ -70x² +64 x + 384.

2007-04-29 22:05:24 · answer #2 · answered by steiner1745 7 · 0 0

if you have roots a,b,c,d the polynomial is
(x-a)(x-b)(x-c)(x-d)
Notice you change the sign of the roots
(x+8)(x+2)(x-3)(x-8)=
x^4-x^3-70*x^2+64*x+384

2007-04-29 22:03:53 · answer #3 · answered by Anonymous · 0 0

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