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john has $6 and he is saving $2 per day. sue has no money and is saving threee dollar per day. solve the problem through using expressions of their savings.

2007-04-29 14:51:02 · 5 answers · asked by thamina 2 in Science & Mathematics Mathematics

5 answers

Let d = number of days

John's savings = 6 + 2d
Sue's savings = 3d

If you are trying to find out when they will be the same and how much they will have, then first just set the equations equal to each other and solve:

6 + 2d = 3d
6 = 3d - 2d
6 = d

Therefore, in six days, they will have the same amount.
That amount is: 3d = 3x6 = $18.
(also, 2d + 6 = 12 + 6 = $18)

2007-04-29 14:56:07 · answer #1 · answered by Anonymous · 0 0

Savings for John is j
Savings for Sue is s

Then
j = 6 + 2d
s = 0 + 3d

d is the number of days
For example for the 5th day, d = 5
then
John has saved j = 6 + 2(5) = 6 + 10 = 16
Sue has saved s = 3(5) = 15

2007-04-29 14:54:54 · answer #2 · answered by looikk 4 · 0 0

Let J stand for John, and S stand for Sue. d stands for days.

J=$6+$2d
S=$0+$3d

You want to find out when they'll have the same amount of money, so you set the equations equal to each other.

J=S
$6+$2d=$0+$3d

Now you proceed to solve.

$6+$2d=$0+$3d
-0 +2d -0 +2d
6=5d
divide by 5 on each side....
6/5= 1.2

thus, John and Sue will have the same amount of money in 1.2 days, or a little over a day.

2007-04-29 15:00:21 · answer #3 · answered by Sally C 1 · 0 0

2w+4(7+3w)= -14 first distribure 4(7+3w) so 4 circumstances 7 is 28 and four circumstances 3w is 12w 2w+28+12w=-14 and prefer words 2w+12w equals 14w 14w+28=-14 subtract 28 to the two factors 14w=-40 two now divide by using 14 on the two factors and w=-3

2016-12-29 17:55:57 · answer #4 · answered by ? 3 · 0 0

So what's the question? You left that out of your post!

2007-04-29 14:54:29 · answer #5 · answered by steiner1745 7 · 0 0

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