A marksman scores a bullseye on 90% of his shots. What is the probability that he gets at least eight bull's eyes if he shoots ten times?
The answer is .92981, I just need to find out how to get the answer. Please help!
2007-04-29 14:30:30 · 3 answers · asked by Toot 3 in Education & Reference ➔ Homework Help
P(at least 8) = P(exactly 8) + P(exactly 9) + P(exactly 10)
= (10C8 * .9^8 * .1^2) + (10C9 * .9^9 * .1^1) + (10C10 * .9^10 * .1^0)
= .1937102445 + .387420489 + .3486784401
= .9298091736
2007-04-29 14:47:52 · answer #1 · answered by Anonymous · 0⤊ 1⤋
You got me, I'd have figured it would be closer to a certainty as he, seems to average 9 bulls for ten shots with a 90%. So 8 out of 10, almost a given? Sorry no help here.
2007-04-29 21:38:10 · answer #2 · answered by Old guy 124 6 · 0⤊ 1⤋
I'm not sure, but I'm thinking that since 9 is 90% of 10, and 8 is less than than 10, it's a little more than 90% than, but I can't figure out how to get the answer...
2007-04-29 21:41:41 · answer #3 · answered by preciouslily1991 2 · 0⤊ 1⤋