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If a 8.30 lb cat absorbs 3.30 × 10−5 KJ of radiation, how many rads did this cat absorb?

2007-04-29 13:26:54 · 1 answers · asked by dandevita 1 in Science & Mathematics Chemistry

1 answers

(3.30 × 10−5 KJ)(1KW-s/KJ)(1 m^2/1.251KW) =
0.2637890 cm^2-s of solar radiation. Divide by area exposed to the Sun in cm^2 to get seconds of exposure.

2007-04-30 12:11:11 · answer #1 · answered by Helmut 7 · 0 0

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