2007-04-29 12:59:53 · 2 answers · asked by ramesh r 1 in Science & Mathematics ➔ Mathematics
The circumference of a circle of radius r is 2πr. The length of an arc with central angle θ is θr. We need to determine the central angle θ that is intercepted by the chord.
The perpendicular bisector of the chord intersects the center of the circle. Now we have a right triangle.
r = radius = hypotenuse = 10
c/2 = one leg = 12/2 = 6
sinθ = (c/2) / r = 6/10 = 3/5
θ = arcsin(3/5) ≈ 36.869898°
But the chord is actually intercepted by an angle of 2θ.
The length of the arc intercepted by the chord is:
L = r(2θ) = 20arcsin(3/5) ≈ 12.8780022 cm
2007-04-29 13:58:04 · answer #1 · answered by Northstar 7 · 0⤊ 0⤋
pi x radius x height
3.14 x 25 x 12 = 942 cm
the 25 is 5 to the second power
(i'm not sure if this is right, but i hope it helps)
2007-04-29 20:12:25 · answer #2 · answered by lady_crysa 2 · 0⤊ 1⤋