Can anyone solve this? I'm confuse.?

Question

Complete the table. Flying with no wind, a plane makes an 840 mi trip in 6 h. On the return trip, the plane flies with a 70mi/h wind.

(the table) rate time distance
no wind ? ? ?
with wind ? ? ?

total distance = _________
total time = ____________
average speed = ________

Answer 1

The question has no answer because we do not know the effects of the wind therefore you can`t calculate the changes it will make.It travels at140 mph without wind but just because it has a 70m/h wind behind it does not mean it will travel 70m/h faster. This is a dumb question

Answer 2

...and now for a SERIOUS answer...

TychaB did everything right, except that in your question you only say "with" a 70mph wind. I would assume this is a tail wind, not a head wind. So..

Plane's air speed = 840/6 = 140mph
With the same air speed plus tail wind,
Ground speed = 140 + 70 = 210mph
Time of return flight = 840/210 = 4 hours.

Total distance = 2 x 840 = 1680 miles
total time = 6 + 4 = 10 hours
average (ground) speed = 1680/10 = 168mph

Answer 3

No Wind, Going To:
Distance = 840 miles
Time = 6 hours
Speed = Distance / Time = 840 / 6 = 140 mph

Wind, Returning:
Distance = 840 miles
Speed = 70 mph
Time = Distance / Speed = 840 / 70 = 12 hours

Total Distance = 840 + 840 = 1680 miles
Total Time = 6 + 12 = 18 hours
Average Speed = Distance / Time = 1680 / 18 = 93.3 mph

Answer 4

First leg speed = 840/6=140
Return speed=140+70=210
Return leg time=840/210=4hours
Total distance=1680
total time=6+4=10
Average speed= 1680/10 =168 mph

Answer 5

Total distance= (840+840=1680 miles)

Average speed on first journey= 840/6 (total miles covered divided by time taken) =140 miles per hour.

Sorry I couldn't help further but wasn't sure how to calculate speed using wind speeds!

Answer 6

Phill and Peter both have the math correct. Answering this kind of HW in this manner does you little good as you don't learnto think for yourself. As to whether the plane really travels 70mph faster in a 70mph tail wind, well as it is suspended in the air, its speed can only be relative to the air. so it is a reasonable assumption that its speed will remain constant relative to the air, so with a tail wind, its ground speed, ie relative to the ground is indeed (70+140)mph. As to its relationship to reality, well take off, and landin are not going to be at same speed as flight speed and it would be most extraordinary for a constant tail wind of 70mph to be a tail wind fro the whole flight including take off and landing. Not to mention turbulance with such high speed winds. Don't think I would be signing up to be piolet or passenger in a plane whose speed is 140mph and which is planning to fly in average wind speeds of gale force.
You might politely ask your math teacher to make problems more true to life.

Answer 7

allow 'A' denote the cost of one apple and 'O' denote the cost of one orange. a million) O = 5+y 2) allow 'T' denote the completed cost of three apples and a million orange. T = (3*y) + (5+y) i.e., T = 3y + 5 + y T = 4y + 5 3) allow 'T' denote the completed cost of three apples and a million orange. Given , T = sixty one pence (3*y) + (5+y) = sixty one 3y + 5+y = sixty one 4y + 5 = sixty one 4y = sixty one - 5 4y = 56 for this reason, y = 56 % 4 y = 14 cost of one apple = 14 pence.

Answer 8

840mi/6h = 140mph

On the return flight, 140mph - 70mph = 70mph

840mi/70mph = 12h

Total distance = 840mi + 840mi = 1680mi
Total time = 12h + 6h = 18h
Average speed = 1680mi/18h = 93-1/3 mph

Answer 9

Disstance = 1m
TT = 1sec
AS = 100mph
Thats with my bum LOL

Answer 10

I'm thinking you should do your homework?