jack was factoring the polynomial 6x^2+27x+30. he decided that the factors are 3(2x-1)(x+5) is he right and why???
2007-04-29 11:27:11 · 5 answers · asked by cobo 1 in Education & Reference ➔ Homework Help
No because after distributing 3 through (2x-1) you get (6x-3) and then that leaves (6x-3)(x+5) after using the FOIL method you obtain the answer 6x^2 + 27x - 15 which is not the polynomial that you started with
2007-04-29 11:33:23 · answer #1 · answered by bnhawk03 3 · 0⤊ 0⤋
No he is not right, that would factor out to 6x^2+27x-15
If u factored that you would get 3(2x+5)(x+2)
2007-04-29 18:31:54 · answer #2 · answered by Gazala K 2 · 0⤊ 0⤋
3(2x-1)(x+5)
3(2x^ + 9x -5)
6X^2 + 27 x -15)
Factoring is not correct.
2007-04-29 18:35:08 · answer #3 · answered by kale_ewart 5 · 0⤊ 0⤋
First divide through by 3
3(2x^2+9x+10)
I don't think he is correct.
(2x-1)(x+5) doesn't expand to 2x^2+9x+10
.
2007-04-29 18:36:16 · answer #4 · answered by Robert L 7 · 0⤊ 0⤋
no...should be
3(2x+5)(x+2)
2007-04-29 18:33:41 · answer #5 · answered by triangelove 2 · 0⤊ 0⤋