a container of oxygen gas in a chem lab room is at a pressure of 6.0 atm and a temp of 27C?

Question

a. if the gas is heated at constant volume until the pressure triples, what is the final temp.

b. if the gas is heated so that both the pressure and volume are doubled, what is the final temp

Answer 1

Gay Lussac's Law.
The Absolute Pressure of a given mass of gas is Directly Proportional to its Absolute Temperature (K) at Constant Volume.

1...6atm at 27°C = 6 atm at 300K
When the Pressure triples (18atm), the Absolute Temp. triples. = 900 K = 627°C.

2...This is the Combined Gas Law.
P1 x V1 x T2 = P2 x V2 x T1
6 x 1 x T2 = 12 x 2 x T1

T2 = (24 x 300) ÷ 6
T2 = 1200 K = 927°C

Answer 2

At constant volume, P is proportional to T (in deg K).
27C = 300K, so:

a. 300 * 3 = 900K = 627C

b. PV = constant *T, so this time the temp goes to 1200K = 927C.

Answer 3

Use the gas law

P1*V1/T1 = P2*V2/T2