One more problem in general form..?

Question

I have one more problem I'm stuck on....
Find the equation in general form ( i.e. Ax + By + C = 0), this is regarding graphing.

Through (1, 2) and parallel to 4x + y - 1 = 0

Answer 1

In GENERAL FORM --- the form you ASKED FOR, it's:

4 x + y - 6 = 0.

That's because to be parallel to the original line, the coefficients of x and y should be the SAME as, or the SAME MULTIPLE of, the original coefficients.

If the line passes through (x, y) = (1, 2), the constant to be SUBTRACTED from 4 x + y must be 4*1 + 2, that is 6.

Hence the solution is 4 x + y - 6 = 0.

Live long and prosper.

Answer 2

4x + y - 1 = 0 translates as y = -4x + 1, so the slope of the known line is -4. Since your line is parallel, its slope is also -4.

y = -4(x) + b
2 = -4 * 1 + b
2 = -4 + b
b = 6

y = -4x + 6

-4x - y + 6 = 0

Answer 3

2 = -4(1) + b

y = -4x + 6

Parallel lines have equal slopes. Using the y = mx + b form of a line will make constructing this line very simple as shown above.

Answer 4

(x1,y1)=(1,2) and m=-4