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For a first order reaction the rate R = −k N so the ratio of rates at two different times is given by R(t1)/R(t2) = N(t1)/N(t2).
For nuclear decay the rate is ofen is expressed in units of counts per unit of time.

A chemists determines that a sample of petrified wood is 3.00 X 103 years old. What is the rate of decay, in counts per minute per gram, of carbon-14 in the sample? The decay rate of carbon-14 in wood today is 13.6 counts per minute per gram, and the half life of carbon-14 is 5730 years.

2007-04-29 07:24:27 · 1 answers · asked by Gemini 2 in Science & Mathematics Chemistry

1 answers

R/13.6 = 3000/5730.

Solve for R.

2007-05-01 00:34:15 · answer #1 · answered by Gervald F 7 · 0 0

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