Exercise about pressure with the Eiffel tower.?

Question

Exercise about pressure with the Eiffel tower.?
I have to do an exercise about pression with the Eiffel tower.
The information they give:

Weight: 73000 Tonnes
Height: 324 metres
Pressure at the ground: 4500 000 Pa

The question: What is the contact at the surface of the ground?

Please help me.
It would be so helpful!

Answer 1

Pressure is defined as force/area. Therefore,
A = F/P = mg/P = 73000*1000*9.8/4 500 000 =
158.98 m²

The height is not required for this answer

Answer 2

This is yet another example of an arcane definition (Pa). Find out what Pa is in standard SI units (e.g., kg-m-sec). Anyhow, once you've done that simply divide the pressure (P)given in Pascals converted to SI units into the weight also in SI units. I'm guessing your Tonne = 1000 kg or a metric ton, but I don't know from what you given me.

Since pressure P = F/A; where F is a force (weight) and A is the area that force is acting on, you can solve for the area A = F/P; where the F is the weight of the tower divided by the pressure. See this is really a very easy physics problem. The only thing difficult about it is that you've been given a bunch of arcane units that have little real meaning in physics.

For example a metric ton (tonne) is not really a weight or force at all. it is a measure of mass (m). To get a weight you need to multiply m by g = 9.81 m/sec^2 so that F = mg = 73000 X 1000 kg/Tonne X 9.81 m/sec^2 to find the force or true weight of the tower. Then you need to convert Pascal to units of kg-m-sec also to find out that area (A) in m^2.

Very little physics, but lots of unit conversion.

PS: height has nothing to do with it.