(x^5)(x^(-3)) = x^5 / x^3 = x^2.
2007-04-29 04:55:04
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answer #1
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answered by Anonymous
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Since both bases are the same (x), all you have to do is add the exponents. For things like this, it's helpful to think of a simpler example.
If we have 2^2 * 2^-1 we can progress as follows:
2^2 * 2^-1=
4 * 1/2=
2=
2^1
All we've done is added the exponents of the original:
2^(2+ -1) = 2^1 = 1
For your problem, we have
x^5 * x^-3 = x^(5+ -3) = x^2
2007-04-29 11:58:49
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answer #2
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answered by Andy B 1
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Add the indices when multiplying.
1. y^5 * y^3 = y^8 , derived from (5+3)
2. y^-5 * y^3 = y^-2 , derived from (-5+3)
3. y^5 * y-3 = y ^2 , derived form [5 + (-3)]
4. y^-5 * y^-3 = y^-8 , derived form [-5 + (-3)]
In you are dividing, subtract the second index form the first index.
2007-04-29 12:07:05
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answer #3
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answered by flandargo 5
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Since x is the base, you just have to add the 2 exponents together and you get x^2
2007-04-29 11:56:56
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answer #4
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answered by Anonymous
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Yes.
x^(5 - 3) = x^2 = xx.
2007-04-29 11:55:11
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answer #5
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answered by Mark 6
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regroup this using the following idea. a^z*a*y=a^(z+y)
so for your problme x^5*x^-3=x^(5-3)=x^2
2007-04-29 11:55:54
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answer #6
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answered by careyschwartz 2
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x^2
When you multiply terms with exponents, you add the exponents.
x^5 * x^-3 =
x^2
2007-04-29 12:09:25
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answer #7
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answered by Kels Kels 2
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