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(ax)^-2

10^-3

[(-4)^2]^-5

(2/3)^-2 (4/5)^-1

2007-04-29 04:38:32 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

(ax)^-2
= 1/(ax)^2

=1/(aaxx)

10^-3
=1/10^3

=1/1000 or 0.001

[(-4)^2]^-5
=-4^-3
=1/4^3

=1/64


(2/3)^-2 (4/5)^-1
=(3/2)^2 (5/4)
=(9/4).(5/4)

=45/16 or 2 & 13/16

2007-04-29 04:47:58 · answer #1 · answered by Simon T 6 · 0 0

1/(ax)^2
.001
1/16^5
(3/2)^2(5/4) = 9/4*5/4 = 45/16

2007-04-29 04:42:09 · answer #2 · answered by bz2hcy 3 · 0 1

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2016-12-10 14:33:44 · answer #3 · answered by ? 4 · 0 0

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