Find the equation of the line with x-intercept 5 and y-intercept 8.?

Answer 1

Use the slope equation ( m = y2 - y1 / x2 - x1) and the two points (0,8) (5,0) to solve for the slope.

0 - 8 / 5 - 0 = -8/5 or 1.6

Then use the slope intercept form (y = mx + b where m is the slope and b is the y intercept) to write an equation for the line.

y = -1.6x + 8

Answer 2

hey, The y intercept is 8, and the x intercept is 5, for this reason the line is going for the time of 5 and down 8. This makes the gradient -8/5. putting this into the equation y=mx+c supplies y=-(8/5)x+8 (Remeber m is the gradient and c is the y intercept) If we multiply this equation by through 5 to get rid of the fractions we get 5y=-8x+40 wish it really is a help.

Answer 3

first, try to picture the line in your mind. you know that when the line crosses the x axis, the value will be 5 and the y value will be 0. and when it crosses the y axis the y value will be 8 and the x value will now be 0. putting in the formula (y2-y1)/(x2-x1) you will get a gradient which is 8/5 = 1.6

now, you have the equation of line formula : y = mx + c
where c is the y intercept . substituting will give

y = -1.6x + 8 (negative gradient because the line is negative)

Hope this helped,
Thanks

Answer 4

The line passes through points 0,8 and 5,0.
Consider a point X,Y on line and look at the graient = difference in Y / difference in X

Y-8/ X = (8 - 0)/ (0 -5)
Y-8 / X = 8/-5
-5Y + 40 = 8X
40 - 8X - 5Y = 0

Answer 5

The line goes thru the points (5,0) and (0,8). So the equation of the line thru the points is:

8x + 5y = 5*8
8x + 5y = 40

Answer 6

slope is -8/5

y=x(-8)/5)+8 (slope y intercept form of linear eq)
y=-8x/5 +8
y =-1.6x +8

Answer 7

The answer is y=-8/5x+8.

Answer 8

y= -8/5x+8

Answer 9

y= -8/5x+8

Answer 10

y=-1.6x+8