If the hypotenuse of a right triangle is 10 and one leg is 5 what is the length of the other leg?

Answer 1

If it's a right triangle. Use the Pythagorean Theorem.

a^2 + b^2 = c^2
(c^2 is always the hypotenuse squared)

5^2 + b^2 = 10^2 (Isolate the b^2)
25 + b^2 = 100 (Subtract 25 from both sides)
b^2 = 75 (To solve for b, take the square root of 75)
b = The square root of 75. (Which is 8.66)

Length of the other leg is 8.66.

But, if the answer is to be left in radical form.
The length of the other leg would be 5√3.

Answer 2

If the other leg has lenght x, then:
x^2 + 5^2 = 10^2
Subtract 5^2 from each side:
x^2 = 10^2 - 5^2
= 100 - 25
= 75
Take the positive square root:
x = sqrt(75)
= sqrt(25)sqrt(3)
= 5sqrt(3).

Answer 3

a^2+b^2=c^2
5^2+b^2=10^2

25+b^2=100
25-25+b^2=100-25
b^2=75
b=sqrt of 75
b=sqrt of 25 x sqrt of 3
b=5 sqrt of 3

Answer 4

square root of 75