Seth has one less than twice the number of compact discs that jason does.Raoul has 53 more CD's than jason has.If seth gives jason 25,seth and jason will have the same number of CD's. How many CD's did each of the 3 boys have to begin with . plz help me
2007-04-29 04:00:15 · 5 answers · asked by sarah 1 in Science & Mathematics ➔ Mathematics
Jason has 26, Seth has 51, and Raoul has 79... I GOT IT!!!!!!!!!!!!!!
2007-04-29 04:11:53 · answer #1 · answered by Anonymous · 0⤊ 0⤋
Seth had 101, Jason had 51, and Raoul had
104.
x + 25 = (2x - 1) - 25
2007-04-29 11:12:39 · answer #2 · answered by Mathlady 6 · 0⤊ 0⤋
okay.
1. S = 2J-1
2. S-25=J+25
3. S = J+50 (add 25 to both sides)
4. 2J-1 = J+50 (substitute the common value S in 1 and 3)
5. 2J = J +51 (add one to both)
6. J = 51 (subtract J from both)
The rest you can work out on your own.
2007-04-29 11:18:07 · answer #3 · answered by open4one 7 · 0⤊ 1⤋
each boy needs to spend more time finding a life than trading Cd's... Lil sorry this makes me nauseous
2007-04-29 11:08:46 · answer #4 · answered by Coco 2 · 0⤊ 0⤋
That makes me dizzy just reading it. What in the world is this going to teach you in real life?
2007-04-29 11:04:09 · answer #5 · answered by greenfrogs 7 · 0⤊ 0⤋