e^x(x^2-1)=0. Solve for x?

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e^x(x^2-1)=0. Solve for x?

2007-04-29 02:00:00 · 3 answers · asked by Monica 1 in Science & Mathematics ➔ Mathematics

There are two seperate terms to the problem: e^x times (x^2 minus 1)

2007-04-29 04:00:24 · update #1

3 answers

e^a = 0 ===> that a = negative infinity,
So (x^2 -1) = 0 ===> x=1 or x = -1

2007-04-29 02:05:02 · answer #1 · answered by a_ebnlhaitham 6 · 1⤊ 0⤋

There is no solution for x in this equation, the reason being that the exponential function is never equal to zero. Natural log both sides and you will get x(x^2-1)=ln0. If you recall, ln0 is not defined, it nears negative infinite.

2007-04-29 09:29:34 · answer #2 · answered by Eric C 2 · 0⤊ 0⤋

Is all this, x(x^2-1), the exponent of e??

2007-04-29 09:07:13 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋