Complete the following:
10p^2-pq-3q^2=(5p-3q) (? )
2007-04-28 23:04:32 · 7 answers · asked by kiara 1 in Science & Mathematics ➔ Mathematics
RHS = (5p - 3q).(2p + q)
2007-04-28 23:10:24 · answer #1 · answered by Como 7 · 0⤊ 0⤋
10p^2-pq-3q^2
Factors of 3: 3,1
Factors of 10: 5, 2
(5x-3q)
( 2x+q)
Hence, 10p^2-pq-3q^2=(5p-3q) (2x+q )
2007-04-29 06:52:57 · answer #2 · answered by Kuan T 2 · 0⤊ 0⤋
let the unknown term be “a”
10p^2 - pq - 3q^2 = (5p - 3q) a
(10p^2 - pq – 3q^2 ) / (5p - 3q) = a
5p – 3q) 10p^2 - pq - 3q^2 ( 2p + q
-(10p^2- 6pq)
---------------------------
0 + 5pq - 3q^2
- (5pq - 3q^2 )
---------------------------
0
--------------------------
(I'm sorry but the yahoo answers' text does not allow me to show you division properly,i.e., it doesn't allow me to allign the terms one below the other as we do in division. but hopefully you will understand the calculations.)
therefore, a = 2p + q
and so, 10p^2 - pq - 3q^2 = (5p - 3q) (2p + q)
2007-04-29 06:48:07 · answer #3 · answered by Anonymous · 0⤊ 0⤋
10p^2 - pq - 3q^2 = (5p - 3q) (2p + 1 )
2007-04-29 06:12:48 · answer #4 · answered by suesysgoddess 6 · 1⤊ 0⤋
10p^2 - pq - 3q^2 = (5p - 3q) (2p + q)
2007-04-29 06:17:37 · answer #5 · answered by detektibgapo 5 · 0⤊ 0⤋
10p^2-pq-3q^2=(5p-3q)(2p+q)
Proof:
5p(2p+q)-3q(2p+q)
10p^2+5pq-6pq-3q^2
10p^2-pq-3q^2 PROVED
Hope to answer the question upto satisfaction.
2007-04-29 06:25:24 · answer #6 · answered by Muhammad Faraz Quadri 2 · 0⤊ 0⤋
(5p-3q)(2p+q)
2007-04-29 06:14:09 · answer #7 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋