i cant believe you would ask that
go count them.
If you did that, you would know by now.
sixty freakin' four
2007-04-28 22:46:58
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answer #1
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answered by D.W.W. 4
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Eight different size squares can be outlined on a checkerboard. The largest, made of 8x8 of the smallest squares, can only have one. There are 64 of the smallest squares and these will be the reference unit. Once you see the pattern you'll notice the following: 64 squares that are 1x1, 49 squares that are 2x2, 36 squares that are 3x3, etc. Add perfect squares: 1+4+9+16+25+36+49+64 for a total of 204.
2007-04-29 03:39:57
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answer #2
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answered by Quasi 1
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Sigma(n^2) for n = 8:
1 + 4 + 9 + 16 + 25 + 36 + 49 + 64 = 204
2007-04-28 22:51:58
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answer #3
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answered by blighmaster 3
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204=1^2+2^2+3^2+4^2+5^2+6^2+7^2+8^2=sigma n^2 n=8
204=1+4+9+16+25+36+49+64=204
2007-04-28 23:31:53
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answer #4
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answered by Dave aka Spider Monkey 7
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Little ones: 64 (8x8)
Total: 204
2007-04-28 22:50:27
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answer #5
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answered by keti2609 2
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8^2 of size 1 x 1
7^2 of size 2 x 2
...
2^2 of size 7 x 7
1^2 of size 8 x 8
Total = sum(k = 1 to 8) k^2
= (1/6)(8)(9)(17)
= 204.
2007-04-28 22:51:59
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answer #6
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answered by Anonymous
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204
2007-04-28 22:47:00
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answer #7
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answered by Kuji 7
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there are 64 squares on a chess board!! not bad for someone that doesn't plays chess!!!
2007-04-28 22:53:37
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answer #8
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answered by Anonymous
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64
2007-04-28 22:46:15
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answer #9
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answered by Mein Hoon Na 7
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I would have to say almost infinity amounts. But that Is just my mind over thinking things.
Each sqare can make four new squares and so on and so on.
2007-04-28 22:50:42
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answer #10
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answered by Anonymous
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64 (8x8)
2007-04-28 22:46:40
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answer #11
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answered by yishor 4
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