How many moles of NH3 can be produced by the reaction of 2.00 grams of N2 with 3.00 grams H2?

Question

Reaction N2(g) + 3 H2(g)>>>2 NH3(g)

Answer 1

MM (N2)= 28 g/mol

2.00 / 28 = 0.0714 mole N2

MM(H2)= 2 g/mol

3 / 2 = 1.5 moles H2

the ratio between N2 and NH3 is 1 : 3 so H2 is in excess and N2 is the limiting reactant

we get 0.0714 x 2 = 0.143 mole NH3

Answer 2

2/28 x 2 x 17

Answer 3

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