express to simpliest form.
2007-04-28 20:42:25 · 10 answers · asked by gomorgango 3 in Science & Mathematics ➔ Mathematics
4root3/root6
= 4 root3 (root2 times root3)
root3 root3 cancel
= 4/ root2
multiply top and bottom by root2
= 4root2/2
= 2root2
2007-04-28 20:45:35 · answer #1 · answered by mahindraoye 2 · 1⤊ 0⤋
2
2007-04-28 22:01:03 · answer #2 · answered by Billie Jean 5 · 0⤊ 0⤋
4√3 / √6 = 4√3 / (√2.√3) = 4 / √2 = 4√2 / 2 = 2√2
2007-04-28 21:51:33 · answer #3 · answered by Como 7 · 0⤊ 0⤋
7 x root3 x (4root6 - root3) = 7 x (root3x 4 root6 - root3 x root3) = 7 x ( 4root18 - 3) = 7 x ( 4root9x2 - 3) = 7 x ( 12root2 - 3) = 7 x 12root2 - 7 x 3 = 84root2 - 21 = 118.seventy 9 - 21 = ninety seven.seventy 9
2016-10-04 02:04:08 · answer #4 · answered by ? 4 · 0⤊ 0⤋
4 root 3 / root 6
= 4 root 3 / ( root 3 * root 2)
= 4 / root 2
= root 8 * root 2 / root 2
= root 8
= root 4* 2
= 2 root 2
rusty.
2007-04-28 20:48:04 · answer #5 · answered by Anonymous · 0⤊ 0⤋
4 root3/root6
2* root 2*root 2*root 3/root2*root 3
finely
2* root 2
2 root 2
2007-04-29 00:27:49 · answer #6 · answered by Anonymous · 0⤊ 0⤋
2 square root 2
2007-04-28 20:56:10 · answer #7 · answered by Lucia O 1 · 0⤊ 0⤋
4sqrt(3) / (sqrt(2)*sqrt(3) = 4/ sqrt(2) = 2^2 / 2^(1/2) = 2^(3/2) =
2sqrt(2)
2007-04-28 20:46:18 · answer #8 · answered by Anonymous · 0⤊ 0⤋
4 sqrt3/ sqrt6 =
= 4sqrt3/(sqrt3*sqrt2) = 4/sqrt2 = 2sqrt2
2007-04-28 20:48:16 · answer #9 · answered by blighmaster 3 · 0⤊ 0⤋
i'm assuming by root you mean sqrt
=sqrt(16)*sqrt(3)/sqrt(6)
=sqrt(16*3)/sqrt(6)
=sqrt(48)/sqrt(6)
=sqrt(48/6)
=sqrt(8)
=2sqrt(2)
2007-04-28 20:50:15 · answer #10 · answered by Anonymous · 1⤊ 1⤋