How many base hits a team can have in 1 inning without scoring a run. Explain your answer.?

Question

One team only. Errors are not hits. By definition in the mlb rule book.

Answer 1

Six.

Single (or double, or triple -- doesn't matter for the first two). Runner picked off (or caught stealing).
Single, runner picked off again.
Single.
Single.
Single -- bases now loaded.
Batter hits grounder that hits one of his teammate runners before an infielder has a chance to make a play -- runner called out, batter credited with single, no run scores. (This would have to be the runner from first or second, as the runner from third is likely in foul territory and not subject to the automatic out rule.)

Answer 2

Chip maker has the right idea, rule 10.05(b) (5) runner is called out for interference with a fielder attempting to field a batted ball, unless in the scorer's judgment the batter-runner would have been safe had the interference not occurred.
The first answer is wrong since a hit is not credited for fielder's choices.

Answer 3

the answer is 7. you are able to't have more advantageous than 7 because of accurate right here rule: Rule 10.08(d) even as a double or triple scouse borrow is tried and one runner is thrown out in the previous reaching and retaining the bottom he's attempting to scouse borrow, no different runner will be credited with a stolen base.

Answer 4

6, but someone has got to teach these guys how to run the bases, because 3 players have been picked off or thrown out on the bases, and 3 stranded at the end if the inning.

Answer 5

Six, Six singles in a row with runners advancing one base and the 1st three being called out at home.

Answer 6

The correct answer is five

Answer 7

Five. I don't need 2 explain.