Find slope and y-intercept then graph: 3y-1=2x. I know the slope = 2/3 and y = 0,1/3. However, I don't know how to graph this. Anyone know?
2007-04-28 18:05:01 · 9 answers · asked by Antonello D 1 in Science & Mathematics ➔ Mathematics
Find another arbitrary point on the graph - say at (-1/2,0). Once you have two points on the graph, draw a straight line passing through both points to give you your graph.
2007-04-28 18:11:39 · answer #1 · answered by gudspeling 7 · 0⤊ 0⤋
The equation you describe indicates a straight line. The y-intercept is where the line intersects the y-axis, so first put a point on the y-axis at x=1/3.
The slope is how much y increases when x increases by 1. Assume that x = 1 in the given equation. Y will increase by the slope, which is 2/3, making it equal to 1. This gives you a second point at 1,1.
Draw a line connecting these two points, and extend it as far as you need to on your graph.
2007-04-28 18:10:58 · answer #2 · answered by mystick358 2 · 0⤊ 0⤋
yes...
m=2/3
if 3y-1=2x, all you have to do is solve for y:
3y=2x+1
y=(2/3)x+(1/3)
in y=mx+b form, m is the slope and b is the y-intercept...
therefore, the coefficient of x=the slope "m"=(2/3)
and b (the constant) in this case is (1/3)
so to graph it all you have to do is start at 1/3 when x=0, and go up two places towards the positive y-axis and three places to the right towards the positive x-axis...
therefore the next point you should connect from (0, 1/3) is (3, 7/3)
2007-04-28 18:10:38 · answer #3 · answered by Anonymous · 1⤊ 0⤋
It is easy find 2 points on the 3y-1=2x , the join them together and since 3y-1=2x is the equation of a line you need only a ruler to draw the graph
2007-04-28 18:36:41 · answer #4 · answered by Ahmad k 2 · 0⤊ 0⤋
you must have ended up with the equation y = 2/3 x - 1/3
if x = 0, y = -1/3
if y = 0,
2/3x - 1/3 = 0,
2/3x = 1/3,
2x = 1,
x = 1/2
so, when x = 0, y = -1/3
when y = 0, x = 1/2
So put 1 point at (0,-1/3) and another at (1/2, 0)
Then draw a line thru both points.
2007-04-28 18:13:26 · answer #5 · answered by Anonymous · 0⤊ 0⤋
3y - 1 = 2x
3y = 2x + 1
y = (2/3)x + (1/3)
For a graph, go to http://www.calculator.com/calcs/GCalc.html
only type in (2/3)x + (1/3)
or you can go to www.quickmath.com
2007-04-28 18:19:56 · answer #6 · answered by Sherman81 6 · 0⤊ 0⤋
y=mx+b
3y-1=2x
3y=2x+1
y=2/3x+1
+1 is your starting pt but the 2/3 is rise over run
2007-04-28 18:10:19 · answer #7 · answered by Kristenite’s Back! 7 · 0⤊ 0⤋
put the equation into y=mx+b.
y = (2/3)x + (1/3)
put x = 0,1,2,3,4,etc. to get y.
then you have graphing coordinates.
2007-04-28 18:18:27 · answer #8 · answered by Anonymous · 0⤊ 0⤋
yeh. but i have no idea how to show u.
2007-04-28 18:07:43 · answer #9 · answered by ♥Penguiin♥ 5 · 0⤊ 0⤋