Adult tickets for a play cost $15 and child tickets cost $14. If there were 23 people at a performance and the theater collected $332 from ticket sales, how many children attended the play?
2007-04-28 16:49:49 · 8 answers · asked by it's-the-daddy 1 in Science & Mathematics ➔ Mathematics
let x =no. of adults
23-x =no. of children
so,
332= 15x + 14(23-x)
332= 15x + 322 - 14x
332= x + 322
332-322= x
10=x
23-x=23-10
23-10=13
13 children attended the play
you may check by:
13x14 + 15x10
182 + 150
$332
2007-04-28 16:56:51 · answer #1 · answered by prophessor 3 · 0⤊ 0⤋
if all adults ... $15 *23 = $345
That $345 - Collected Amount $332 = $13 difference
since children tickets cost $1 less than adults...
13 children
13 children - 23 total people = 10 adults...
to check
10 adults @ $15 = $150
13 kids @ $14 = $182
$150 +$ 182 = $332 total collected
2007-04-29 00:02:24 · answer #2 · answered by SingleMalt 2 · 0⤊ 0⤋
What a ripoff for kid tickets! Let X be the adult and then 23-X must be the kids (it's amazing how many people can't figure this out). Moving along, the total proceeds are sum of each group x price of ticket for a person in that group.
So 15 X + 14 (23-X) = 332
Solve for X, 23-X is the number of kids.
2007-04-28 23:55:27 · answer #3 · answered by cattbarf 7 · 0⤊ 0⤋
let x be the number of children
then, since there are totally 23 people, so the number of adult is 23-x
money collected from adult is $15(23-x)
money collected from children is $14x
total money collected = 15(23-x) + 14x = 332
345 -15x +14x = 332
- x = 332 -345 .............. (subtract both sides by 345)
- x = -13
x = 13
13 children attended the play.
2007-04-28 23:58:00 · answer #4 · answered by Phoenix S 2 · 0⤊ 0⤋
let number of adults attending play= a
let number of children attending play=c
15a+14c=332 (1)
(theater collected $15 from each adult attending and $14 from each child attending)
a+c=23 (2)
(adults and children combined are 23 people)
therefore
a=23-c (3)
sub (3) into (1)
15(23-c)+14c=332
345-15c+14c=332 (expand LHS)
14c-15c=332-345 (take 345 from both sides)
-1c=-13 (simplify)
c=13 (multiply both sides by -1)
there were 13 children at the play
there were also 10 adults
2007-04-29 00:09:31 · answer #5 · answered by Anonymous · 0⤊ 0⤋
9
2007-04-29 00:11:33 · answer #6 · answered by CupCakeafer™ 5 · 0⤊ 0⤋
23children=322
15-14=1
332-322=10
10/1=10
23-10=13
10 adults and 13 children
2007-04-28 23:53:13 · answer #7 · answered by sengpeing 2 · 1⤊ 0⤋
10 aduts 13 kids
(10 x $15.00) + (13 x $ 14.00)=
$150.00 + $182.00 = $ 332.00
2007-04-29 00:05:49 · answer #8 · answered by smart girl 2 · 0⤊ 0⤋