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Use elimination to solve the system of equations given by 10x - 40y = 60 and 15x + 40y = -10.
(0, 1)
(1, 1)
(-2, -2)
(2, -1)

2007-04-28 16:40:32 · 10 answers · asked by Anonymous in Science & Mathematics Mathematics

10 answers

10x - 40y = 60 & 15x + 40y = -10
10x - 40y + 15x + 40y =60 -10
25x =50
x=2
10(2)- 40y = 60
20-40y=60
-40y=40
y=-1
so answer is (2,-1)

2007-04-28 16:45:34 · answer #1 · answered by sengpeing 2 · 0 0

Add the equations and you get 25x = 50. So x = 2. Plug that into the first equation and you get 20 - 40y = 60, so y = -1. The answer is d.

2007-04-28 16:44:08 · answer #2 · answered by Amy F 5 · 0 0

10x - 40y = 60 ......(1)
15x + 40y = -10 ....(2)

Using the method of elimination,

(1) + (2):
10x - 40y + 15x + 40y = 60 + (-10)
25x = 50
x = 2

Sub x = 2 into (1):
10(2) - 40y = 60
-40y = 60 - 20
y = -1

Therefore, x =2, y = -1 a.k.a. (2 , -1)

2007-04-28 16:48:16 · answer #3 · answered by rfedrocks 3 · 0 0

10x-40y=60
15x+40y= -10
if you combine the two equations, (add the values up and down)
you get 25x=50 so x=2
since you know x=2 the only ordered pairs with that choice is the last one so thats the answer

2007-04-28 16:46:22 · answer #4 · answered by Anonymous · 0 0

Well, look at these equations:

(0,1): 10(0) - 40(1) = -40
(1,1): 10(1) - 40(1) = -30
(-2,-2): 10(-2) - 40(-2) = 60
(2,-1): 10(2) - 40(-1) = 60

So you can eliminate the first two. Then

(-2,-2): 15(-2) + 40(-2) = -110

So if one of them is correct, it has to be (2,-1). But check it.

15(2) + 40(-1) = -10

2007-04-28 16:46:28 · answer #5 · answered by TychaBrahe 7 · 0 0

If you just want the answer, the correct answer is (2, -1)
meaning, x = 2 , y = -1
You must be wondering how to get that answer! Well, there are two equations. Solve for x in one equation, and plug in that value of x in the second one. You will get the value of y, which is -1. Then, plug in the value of y in either of the equations and you will get the value of x.
This is one method of solving it. The other method is to add the equations together, and solve for one variable. Then, plug in that value in either of the equations and get the value of second variable.
Hope this helps! Good Luck!

2007-04-28 16:48:56 · answer #6 · answered by A.Samad Shaikh 2 · 0 0

(2, -1

2007-04-28 22:10:40 · answer #7 · answered by Billie Jean 5 · 0 0

(2,-1)

2007-04-28 17:13:30 · answer #8 · answered by icangels92691 2 · 0 0

by using fact that is diverse decision you're able to be able to desire to easily plug in each and each set of numbers, yet you will have the potential to sparkling up it in case the subsequent hw project isn't diverse decision. attempt including the two equations mutually. then you definately gets -7x + 7x = + 3y - 2y = 14 - 14, or y = 0. by using fact that is multiplle decision and easily one decision includes y = 0, we are able to already get that the respond is a. If it weren't diverse decision, you're able to be able to desire to plug y = 0 into the 1st equation, making it -7x = 14. Divide the two aspects by potential of -7 and you get x = -2.

2016-12-28 03:23:17 · answer #9 · answered by ? 3 · 0 0

the last choice

2007-04-28 16:47:59 · answer #10 · answered by :) 5 · 0 0

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