In order to get the expected Mendelian ratio in a monohybrid cross, it is important to be able to observe?

Question

more recessive phenotypes than dominant phenotypes,
one phenotype for each genotype that is expected,
four offspring, one for each box in the Punnett square,
many offspring

Answer 1

D. many offspring

Since the offspring result from chance meetings of gametes, and since the Punnett square only gives the expected ratio of offspring, the more offspring you can observe, the closer to the expected ratio the results will be.

Answer 2

I would think the more recessive phenotypes than dominant phenotypes. Mendelian means that one X chromosome is randomly not used.

Answer 3

If the initial organisms are real breeding (ie. homozygous for a particular function) then: In a monohybrid bypass the F1 era might want to all be heterozygous and the F2 era might want to have a three:a million ratio with 25% being homozygous dominant, 50% being heterozygous and 25% being homozygous recessive. contained in the celebration of the dimensions of pea plants, T is tall and t is short. in case you bypass TT with tt all offspring will be Tt. Then in case you bypass Tt and Tt you get 25% TT, 50% Tt and 25% tt which resources a three:a million ratio of tall to short. In a dihybrid bypass the F1 era might want to all be heterozygous for both features and the F2 era might want to instruct a 9:3:3:a million ratio. contained in the celebration of pea structure and shade, R is round, r is wrinkled, Y is yellow and y is eco-friendly. in case you bypass a RRYY with a rryy then all offspring will be RrYy. Then in case you bypass 2 RrYy plants you receives a 9:3:3:a million ratio of round yellow to round eco-friendly to wrinkled yellow to wrinkled eco-friendly.