Iron has a density of 7.86 g cm-3. How many pounds does a block of iron with a volume
of 1.65 cubic feet weigh? 1pound = 0.4536 kg, 1 foot = 12 in., 1 in. = 2.54 cm.
2007-04-28 13:57:00 · 4 answers · asked by dimo_e7 2 in Science & Mathematics ➔ Chemistry
Iron has a density of 7.86 g cm-3. How many pounds does a block of iron with a volume
of 1.65 cubic feet weigh? 1pound = 0.4536 kg, 1 foot = 12 in., 1 in. = 2.54 cm.
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can you show how you solved it?
2007-04-28 14:04:13 · update #1
Using these details, can somebody show me the way to solve it?
2007-04-28 14:12:42 · update #2
convert 7.86g/cm^3 into lb/ft^3:
7.86g/cm^3*(30.48cm)^3/ft*.002204lb/g = 490.5lb/ft^3
490.5lb/ft^3*1.65ft^3 = 809.3lb
2007-04-28 14:01:55 · answer #1 · answered by Matt 3 · 0⤊ 1⤋
D = m/V
m = DV
Simply convert from the English units using the conversion factors given, then use the density formula to calculate the mass and convert it back to pounds.
2007-04-28 14:03:38 · answer #2 · answered by physandchemteach 7 · 0⤊ 0⤋
density of gold = 19.3 g/cm³ = 19.3(one thousand/e-6) = 19.3(e3/e-6) = 19.3e9 = 19.3e9 kg/m³ mass of gold = 6.00e2 g = 6.00e2 x 1e-3 = 6.00e-a million = 0.six hundred kg density = mass/quantity quantity = mass/density = 0.six hundred/19.3e9 = 0.0311e-9 m³ ANS SI contraptions quantity = mass/density = six hundred/19.3 = 31.a million cm³ ANS cgs contraptions
2016-12-29 14:10:40 · answer #3 · answered by Anonymous · 0⤊ 0⤋
1.65 ft^3 = 46,720 cm^3
46,720* 7.86 = 367.2192kg
367.2192 kg = 809.58 lb
2007-04-28 14:04:27 · answer #4 · answered by Josh G 2 · 0⤊ 0⤋