For the first one I got 3/4 and the second one -a√2 but I am not sure.
2007-04-28 12:58:55 · 4 answers · asked by wzord 1 in Science & Mathematics ➔ Mathematics
You're correct on both
2007-04-28 13:02:46 · answer #1 · answered by April 6 · 0⤊ 0⤋
including fractions whilst the two denominators is a similar is easy: basically upload the numerators. Numerator = area on precise. a/ok + b/ok = (a+b) / ok on your difficulty: 3/20 + 6/20 = (3+6) / 20 To simplify, you seem for a typical element between the numerator of the respond and its denominator (the backside area). to illustrate, in case you have a fragment like 60/420, you will discover that 10 is a typical element (they the two end with a nil); to simplify, you may divide the two via 10 60/420 = 6/40 two Now, you may observe that they proportion 2 as a typical element (they're the two even), so which you divide via 2 6/40 two = 3/21 Now, we see that 3 is a typical element 3/31 = a million/7 it fairly is the simplified version. a majority of those fractions have a similar fee; the single with the smallest numbers is the main undemanding version: 60/420 = 6/40 two = 3/21 = a million/7
2016-10-14 01:10:07 · answer #2 · answered by ? 4 · 0⤊ 0⤋
I can't tell what's under the radical and what's not,
If they're like this, you're right.
sqrt(9/16) = 3/4
asqrt8 - 3sqrt(2a^2) =
2asqrt2 - 3asqrt2 =
-asqrt2
2007-04-28 13:08:35 · answer #3 · answered by Steve A 7 · 0⤊ 0⤋
It is hard to tell where your root sign is the 1st one 3/16
2007-04-28 13:08:22 · answer #4 · answered by dwinbaycity 5 · 0⤊ 0⤋