Here's the question: 2x^2 - 8 = 0 I'm suppose to find the zeros of the parabola. When I factored it I got 2(x-2)(x+2) so i'm guessing the zeros are +2 & -2 but for some reason my book says the zeros are 0 & 4....so can some one help me, tell me if i did it wrong or maybe my book was wrong? thanks alot.
2007-04-28 11:05:11 · 4 answers · asked by Laydee-soul 2 in Science & Mathematics ➔ Mathematics
2x^2 - 8 = 0
2(x^2-4)=0
x = +2 and x = -2.
0 and 4 do not check.
2007-04-28 11:11:43 · answer #1 · answered by fcas80 7 · 0⤊ 0⤋
If that is really the equation (no x^1 terms), then you are right and the book is wrong. You don't even have to factor it; just tansform it to 2x² = 8âx² = 4âx = ±2
2007-04-28 18:14:43 · answer #2 · answered by Steve 7 · 0⤊ 0⤋
I'm inclined to agree with you.
I got -2 and +2 also. Maybe we are both missing something, but I don't know what.
2007-04-28 18:16:51 · answer #3 · answered by Robert L 7 · 0⤊ 0⤋
You are right. The book is wrong.
2007-04-28 18:12:04 · answer #4 · answered by Anonymous · 0⤊ 0⤋